IIT-JEE Pattern
According to new pattern of IIT JEE 2016 every student have to sit for 2 exams i.e.
IIT JEE Main (conducted by CBSE) and IIT JEE Advanced (conducted by IIT) to get
into the India’s top most engineering colleges. 1.5 lakh students who clear IIT
JEE Main are eligible to sit for IIT JEE Advanced. For the final merit list for
IIT Mains 40 percent weightage is given to the CBSE marks in the overall score and
for IIT Advanced the merit list is prepared by taking students from the top 20 percentile
in the respective XII board exams and the marks scored in the IIT advanced exam.
Acharya Institute ensures success by giving proper attention on +2 board exams &
IIT JEE Entrance Exam Preparation as excellence in both the exams is required for
cracking competitive exams.
JEE Main composite score calculation through normalization of Class
XII scores - Most of the JEE Main aspirants must be aware
of the fact that JEE Main Rank List is prepared after finding a composite score
of JEE Main scores and Normalized Marks of Class XII in the ratio of 60:40. But
very few know what actually is this normalization procedure and how normalized score
for class 12th results are calculated. JEE Main Merit Ranks form the basis of the
admissions to undergraduate engineering courses at prestigious 31 NITs, 18 IIITs,
18 GFTIs and many other engineering institutions across India.
Percentage of marks and Percentile are though related but completely different The Percentage
of marks and Percentile are totally different entities. Percentage is your marks
out of a total of 100, whereas percentile score of a candidate reflects percentage
of candidates scoring below a particular candidate in that exam.
Calculation of percentile of a candidate: The percentile score
of a candidate shows the score of the candidate with respect to the number of students.Thus
we calculate the percentile score as below: Number of candidates in
the group with aggregate marks less than the candidate x 100 Total number of the
candidates in the group Let’s understand it more clearly
with the help of few examples-> Suppose in a particular board, the
total number of candidates registered is 13918 and number of candidates appeared
is 13711, the percentile of the candidate will be calculated in the following way-
Example 1: Where a student has scored 50% in the exam and there
are 2218 candidates, who have scored less than the candidates, i.e., less than 50%:
2218 x 100 = 16.18 13711 Here, the percentile score of the candidate from exam
is 16.18 while his/her percentage in the exam is 50%. Example 2:
Where a student has scored 60% in the exam and there are 6865 candidates, who have
scored less than the candidates, i.e. less than 60%: 6865 x 100 = 50.07 13711
Here, the percentile score of the candidate is 50.07 while his/her percentage is
60%. Example 3: Where a student has scored 90% in the exam and
there are 13615 candidates, who have scored less than the candidates, i.e. less
than 90%: 13615 x 100 = 99.3 13711 Here, the percentile score of the candidate
from the exam is 99.3 while his/her percentage is 90%. Subjects considered for
Percentile Score: Five subjects will be taken into account for
calculation of percentile and normalization of qualifying examination marks for
paper 1 (B.E./B. Tech.) and paper 2 (B. Arch./B. Planning) of JEE Main. These subjects
are:
- Language,
- Physics,
- Mathematics,
- Any one of (Chemistry, Biology, Biotechnology, Technical Vocational Subject),
- Any other subject